find midpoint of side BC of triangle ABC, with A(1,-4) and the midpoints of the sides through A being (2,-1) (0,-1)
Here
A ( 1, -4 )
here P (2 ,-1 ) is the midpoint of AB
'' Q ( 0 , -1 ) is the midpoint of AC
Using the mid point formula
P ( 2, -1 ) = [ (x1 + x2 ) (1/2 ) ] p ( 2 , -1 ) = [ (y1 + y2 ) (1/2 ) ]
p (2) = [ (1 + x2 ) (1/2 ) p (-1) = [ ( -4 + y2 ) (1/2 ) ]
4 =1 + x2 -2 = -4 + y2
x2 =3 y2 = 2
So, THE POINTS OF B IS ( 3,2 )
To find C u need to use the method
A ( 1, -4 )
here P (2 ,-1 ) is the midpoint of AB
'' Q ( 0 , -1 ) is the midpoint of AC
Using the mid point formula
P ( 2, -1 ) = [ (x1 + x2 ) (1/2 ) ] p ( 2 , -1 ) = [ (y1 + y2 ) (1/2 ) ]
p (2) = [ (1 + x2 ) (1/2 ) p (-1) = [ ( -4 + y2 ) (1/2 ) ]
4 =1 + x2 -2 = -4 + y2
x2 =3 y2 = 2
So, THE POINTS OF B IS ( 3,2 )
To find C u need to use the method