find out ka for 0.01 M HCN acid having pOH is 10 Share with your friends Share 5 Geetha answered this pH = 14 - pOH = 14 - 10 = 4[H+] = A.log (-4) = 10-4[H+] = Ka×C10-4 = Ka×C10-4 = Ka×0.010.01 Ka = 10-8Ka = 10-80.01 = 10-6 15 View Full Answer
