find out ka for 0.01 M HCN acid having pOH is 10

pH = 14 - pOH     = 14 - 10    = 4[H+] = A.log (-4)        = 10-4[H+] = Ka×C10-4 = Ka×C10-4 = Ka×0.010.01 Ka = 10-8Ka = 10-80.01 = 10-6

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