find out the following in the electric circuit given in the figure. a) effective resistance of two 8 ohm resistors in the combination b) current flowing through 4ohm resistors c) potential difference across 4ohmresistors D) power dissipated in 4 ohm resistor e) difference in ammeter readings if any. Share with your friends Share 49 Jyoti Pant answered this (a) For the parallel combination of 8 ohm resistors,1Rp=18+18=28=14Or Rp=4 ohm(b) Total resistance in the circuit,R=4+RpR=4+4=8 ohmCurrent flowing through circuitI=VR=88=1 A(c) Potential difference across 4 ohm resistorV=IR=1×4=4 V(d) Power dissipated in 4 ohm resistorP=VI=4×1=4 W(e) There is no difference in the readings of ammeters A1 and A2 as same current flows through all elements in a series current. 74 View Full Answer Dr. Utkarsh Jindal answered this a) 1 / Rp = 1 / R1 + 1 / R2 1 / Rp= 1 / 8 + 1 / 8 = 1 / 4 R = 4 ohms b) V = 8 V R = 4 ohm I = V / R I = 8 / 4 I = 2 Ampere c) P.d. = ? I = 2 A R = 4 ohm V = R . I V = 4 x 2 = 8 V d) P = V . I P = 4 x 2 = 8 Watts e) Now both in series and parallel condition R = 4 ohms V = 8 Volt Reading of A1 Ammeter = V / R = 8 / 4 = 2 Ampere Reading of A2 Ammeter = V / R = 8 / 4 = 2 Ampere Difference in ammeter = 2 - 2 = 0 47 Vedangi Agarwal answered this thanku so much @utkarsh 3
