Find range of f(x)=1/(2+3sinx). Share with your friends Share 3 Vipin Verma answered this As we know -1≤sinx≤1⇒-3≤3sinx≤3⇒-3+2≤2+3sinx≤2+3⇒-1≤2+3sinx≤5⇒-1≤12+3sinx≤15⇒-1≤f(x)≤15So Range is -1,15 5 View Full Answer
