find range of f(x)=3sin(root(pi2/16) -x2)

the given function is f(x)=3.sinπ216-x2
since the quantity within the square root can not be negative.
therefore
π216-x20x2π216-π4xπ4
the minimum value of the function is 3.sin0=0
and the maximum value of the function is 3sinπ4=32

therefore range is 0,32
hope this helps you
 

  • 28
What are you looking for?