Find six angles for which sin theta = - square root 3 / 2? Share with your friends Share 4 Anuradha Sharma answered this sinθ=-32=-sinπ3=sin4π3Now general solution can be given as, sinθ=sin4π3θ=nπ+-1n4π3Now putting the value of n = 1, 2,3 ,4 ,5, 6 you can get the 6 different value.try to do it for your own practice -26 View Full Answer
