Find square root of -4 + root( 8 + 16cosec4 theta + sin4 theta) Share with your friends Share 7 Ashwini Kumar answered this We have,8+16cosec4θ+sin4θ=sin4θ+8+16cosec4θ=sin2θ2+2×sin2θ×4cosec2θ+4cosec2θ2=sin2θ+4cosec2θ2∴8+16cosec4θ+sin4θ=sin2θ+4cosec2θ2=sin2θ+4cosec2θNow,-4+8+16cosec4θ+sin4θ=-4+sin2θ+4cosec2θ=sin2θ-4+4cosec2θ=sinθ2-2×sinθ×2cosecθ+2cosecθ2=sinθ-2cosecθ2=sinθ-2cosecθ 16 View Full Answer
