find tha nature of the roots, if b>a, (x-a)(x-b)-1=0.

Dear student
We have,(x-a)(x-b)-1=0x2-bx-ax+ab-1=0x2-(a+b)x+(ab-1)=0Discriminant,D=B2-4AC=-a+b2-41ab-1where A=1,B=-(a+b) and C=ab-1=a2+b2+2ab-4ab+4=(a-b)2+4>0which means roots are real and distinct
Regards

  • 0
What are you looking for?