Find the 9th term in the expansion of ( 3x - 1 / 2 x) to the power of 8, - Maths - Binomial Theorem

Question

Find the 9th term in the expansion of ( 3x - 1 / 2 x) to the power
of 8, x is not equal to 0?

Varun.Rawat · Accepted Answer

We know that r+1th term in the expansion of x-yn istr+1  = -1r  Crn xn-r yrNow In the expansion of 3x - 12x8, the 9th term is,t9 = t8+1 = -18 C88 3x8-8 12x8 = 1256x8

Find the 9th term in the expansion of ( 3x - 1 / 2 x) to the power of 8, x is not equal to 0?