Find the actual capacity of vessel as shown in the figure if the radius of the base is 3.5 cm and height of cylindrical part is 6cm

Please find this answer

volume of cylinder= pi*r²*h
=> r=3.5,h=6cm
22/7*3.5*3.5*6=231 cm²

Answer is here

Sanjana u forgot there is 1 decimal also of 3.5 Shlok is square of 3.5 there are two decimal I am 101 percent sure about my answer Please like it

the vessel has a bump at the bottom thus its volume decreases
actual volume of vessel is= real volume - volume of bump
                                          = pi r² h - 2/3 pi r3
                                           = pi r²(h-2/3r)
​                                           = pi r² ( 6 - 2/3  X  3.5)
                                           = 22/7 * 3.5 * 3.5 * 3.7
                                           = 142.45 cm³
 

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