find the algebraic expression to compute the third number of arithmetic sequence using first and second numbers

Let arithmetic sequence with first and second number be : 3, 6, ...
now to find third number
Solution =
a = 3, d = common difference = 6-3 = 3
Third number = a+2d=3+2(3)=3+6=9
Similarly, a+3d = fourth term
Hope it helps you.
Regards!

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X3=X1+2d
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