find the amount and the compound interest on rupees 8000 for 4 years at 10% per annum interest reckoned yearly.

P = ₹8,000

R = 10 % p.a.

T = 1 1/2 year = 3/2 years

Solution

When the interest is compounded half - yearly

A = P(1+R/200)^2n

= 8,000(1+10/200)^2 × 3/2

= 8,000(200+10/200)^3

= 8,000(210+200)^3

= 8,000(21/20)^3

= 8,000 × 9,261/8,000

= ₹9,261

P = ₹8,000

R = 10 % p.a.

T = 1 1/2 year = 3/2 years

Solution

When the interest is compounded half - yearly

A = P(1+R/200)^2n

= 8,000(1+10/200)^2 × 3/2

= 8,000(200+10/200)^3

= 8,000(210+200)^3

= 8,000(21/20)^3

= 8,000 × 9,261/8,000

= ₹9,261