Find the angle between two vectors 𝚤̂ - 2𝚥̂ + 3𝑘 and 3𝚤̂ - 2𝚥̂ + 𝑘 Share with your friends Share 0 Vipra Mishra answered this Dear Student Given vectorsa→=i^ - 2j^ +3k^b→=3i^ - 2j^ +k^a→ =12 +- 22 +32 =14b→ =32 +- 22 +12 =14a→.b→ = i^ - 2j^ +3k^·3i^ - 2j^ +k^ =3+4+3 =10Also,a→.b→ =a→.b→ cosθ =1414cosθ ⇒10 =14 cosθ ⇒cosθ =1014 =57⇒θ = cos-157 Regards 1 View Full Answer