Find the angle which a line perpendicular to the line x-y+1=0 makes with the positive direction of x axis Share with your friends Share 0 Vijay Kumar Gupta answered this The equation of line is, x-y+1=0Write this in slope intercept form x-y+1=0 -y=-x-1 y=x+1Compare with y-mx+c, we haveThe slope of the line x-y+1=0 is m=1Let the slope of line perpendicular to x-y+1=0 be m'Then it implies that, m m'=-1 m'=-1 (since m=1)Let θ be the angle whcih this perpendicular line makes with the positive direction of x-axis, then tanθ=m' tanθ=-1 tanθ=-tanπ4 tanθ=tanπ-π4 tanθ=tan3π4 θ=3π4 4 View Full Answer