Find the angle which is double to its supplement
let one of the angle be x
therefore the other angle = 2x
so by the given condition,
2x + x = 1800 [as measures of supplementary angles = 1800]
that implies 3x= 1800
that implies x = 180/3 = 600
therefore the 1st angle = 600
therefore the other angle = 60 X 2= 1200
hope this helps. [0 = degree]
therefore the other angle = 2x
so by the given condition,
2x + x = 1800 [as measures of supplementary angles = 1800]
that implies 3x= 1800
that implies x = 180/3 = 600
therefore the 1st angle = 600
therefore the other angle = 60 X 2= 1200
hope this helps. [0 = degree]