Find The Angle Which Vector A=3i+6j+2k Makes With The Coordinate Axes

A = 3i + 6j+ 2k  ; B = i (x axis) then,
  A.B = 3.1 + 6.0 + 2.0  = ABcos theta
    3 = 7 cos theta 
   cos theta = 3/7
     theta = cos inverse of 3/7  (where theta is angle with x axis )
       simmilarly we can proceeed for y axis ,
     vectors in this case are ---- A =  3i + 6j + 2k ; B = j (y axis )
         
    Regards,
       Srinivasa Ramanujan

  • 6
22.5 degree
  • -2
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