Find the answer of 11 and 12 questions

Dear student,

Here is the solution to your question-

 
∆ABC is an equilateral triangle.
Let the side of the equilateral ∆ABC be a cm.
P is a point in the interior of the ∆ABC. PQ⊥BC, PR⊥CA and PS⊥AB
Let PS = 14 cm, PQ = 10 cm and PR = 6 cm
Area of ∆ABC = Area of ∆APB + Area of ∆BPC + Area of ∆CPA


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