Find the answer please quickly to the given question

Dear Student,

To which extent a gas can be liquified depends upon its critical temperature and Vander waals forces of attraction.
That is greater the critical temperature, more easily the gas will be liquified.
Below is the critical temperature of these gases :

NH3=406K
Cl2=417K
SO2=430K
CO2=304K
 
Now, below given is the Vander waals equation :
(P+n2aV2) (V-nb)=nRT     (For n number of moles)where P is pressure, V is volume, R is universal gas constantand T is temperature.a and b are Vander waals correction that is Vander waals forceof attraction constant.'a' is basically said to be measure of intermolecular force.

Liquifaction of gases is directly proportional to 'a'(intermolecular force) which means greater the value of
'a', greater will be liquifaction of gases.That is large value of 'a' coefficients indicates relatively strong
intermolecular force of attraction. And value of 'a' is greater for SO2 gas in comparison to Cl‚Äč2 gas
,therefore SO2 will be liquified more easily.
For SO2,
value of a=6.71
For Cl2,
value of a=6.49

From here we can say that SO2 will liquified more easily in comparison to Cl2.

Hence the correct option will be (3)

Regards

  • 0
What are you looking for?