Find the area of a pentagon ABCDE in which AC=8cm BF=3cm AD=15cm CG=7cm HE=5cm Share with your friends Share 4 Lovina Kansal answered this Dear student Area of △ABC=12×AC×BF=12×8×3=12cm2Area of △ACD=12×AD×CG=12×15×7=52.5cm2Area of △DEA=12×AD×HE=12×15×5=37.5cm2So, Area of ABCDE=Area of △ABC+Area of △ACD+Area of △ADE=12+52.5+37.5=102cm2 Regards 7 View Full Answer Aveg Ganorkar answered this area(ABC) = 8 X 3 = 24 UNIT SQ -1 area(ACD) = 15 X 7 = 105 UNIT SQ, -2 area(ADE) = 5 X 15 = 75 UNIT SQ. -3 AREA of pentagon = (1)+(2)+(2) = 24+105+75 = 204 Unit Square 1
