Find the area of field ABCDEFGH(of the given figure), in which BC=28m,
BG=21m,
AM=18m
DN=12.8m, and
ED=14m

Dear Student.

Since BCFG is a rectangle,so area =length × breadth=BC×BG=28×21=588 m2Area of ABG=12×base×height=12×21×18=189 m2Area of trapezium EDCF=12(Sum of parallel sides)×height=12×(ED+FC)×ND=12×(21+14)×12.8=6.4×35=225 m2So total area of the given figure=189+225+588=1002 m2

We hope that this answer solves your query.
Regards.

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