find the area of the region bounded by the parabola y^2=2x n the straight line x-y=4. Share with your friends Share 2 Vishvesh Kumar answered this Intersection point of the parabola y2=2x and line x-y=4 y2=2(4+y) ⇒ y2=2y+8 ⇒y2-2y-8=0⇒y=4, -2 so x =8, 2 Hence,intersection point is (8,4) and(2,-2)So the Area bound between line and parabola = ∫-2 4(4+y-12y2)dy =4y+y22-16y3-24=16+162-646--8+2+86=18 sq. units 5 View Full Answer