Find the area of triangle ABC in which BC=8 cm , AC=15 cm and AB=17cm. Find the length of altitude drawn on AB Share with your friends Share 1 Vijay Kumar Gupta answered this The semi perimeter is given by, s=AB+BC+AC2 =17 cm+8 cm+15 cm2 =40 2cm =20 cmThe area of the traingle is given by Heron's formula, Area△ABC=s s-a s-b s-c =20 20-17 20-8 20-15 =20 3 12 5 =2×2×5 3 2×2×3 5 =2×2×3×5 =60 cm2Note that the area of △ABC is also given by the formula, area △ABC=12×base×altitude area △ABC=12×AB×altitude Substitute the values to get, 60 =12×17×altitude altitude= 60×217 = 12017 =7.06 cm approx 9 View Full Answer Harsh Mittal answered this 7.05 cm -1 Kartik Tyagi answered this As we know that, area of a triangle= [s(s-a)(s-b)(s-c)]^1/2 Here s=20 cm Therefore, ar.(Triangle ABC)= [20(20-17)(20-15)(20-8)]^1/2 which is equal to 60 cm^2 Now, Area of a triangle= 1/2 * base * altitude Therefore, 60 = 1/2 * 15 * altitude Solving further we get: Alritude= 8 cm 0
