Find the base of a triangle whose area is 0 48 dm^2 and altitude is 8cm - Maths - Perimeter and Area

Question

Find the base of a triangle whose area is 0 48 dm^2 and altitude is
8cm

Vikas Mahala · Accepted Answer

Dear student, $G i v e n, Area of triangle = 0 48 {d m}^{2} = 0 48 \times 100 {c m}^{2} = 48 {c m}^{2} (1 {d m}^{2} = 100 {c m}^{2})$ And, altitude = 8 cm Therefore, $A r e a o f t r i a n g l e = \frac{1}{2} \times B a s e \times A l t i t u d e 48 = \frac{1}{2} \times B a s e \times 8 \Rightarrow B a s e = 12 c m$ Hence, the base of the triangle is 12 cm Regards

Find the base of a triangle whose area is 0.48 dm^2 and altitude is 8cm.