Find the change in the gravitational potential energy of a body of mass 50 kg, when it is moved from the surface of the earth to a point at a height twice the radius of earth. Given radius of earth

Dear Student,

Please find below the solution to the asked query:If potential energy of a body of mass m on the surface of earth is taken as zero then its potential energy at height h above the surface of earth is-P.E.=GmMhR(R+h)h = 2R , m =50 Kg         =GM×50×2RR(R+2R)         = 100 ×G ×M3R=100GM3R

 

 

 


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