Find the change in volume, which 1 m3 of water will undergo when taken from the surface of bottom of sea 1 km deep. Given the elasticity of water is 20,000 atm.

Here,
Let ΔV be the change in volumeh = 103 mV0 = 1 m3B = 20,000 atm  = 2×109 pa
We have
B = σ/(ΔV/V0)
Pressure at a depth of 1000 m will be, P = hρg = 103×103×9.8 = 9.8×106 pa
Assuming the volume to be cubicA
= 1m2σ
= 9.8×106/1ΔV
= (σV0)/B 
= 9.8×106×1/(2×109
= 4.9×10-3 
= 5×10-3 m3 

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