find the circumference of the fifth bohr orbit of an electron whose de-brogile wavelength corresponds to translation kinetic energy of - Chemistry - Atomic Structure

Question

find the circumference of the fifth bohr orbit of an electron whose
de-brogile wavelength corresponds to translation kinetic energy of
h at 27 degree celsius

Geetha · Accepted Answer

Translational kinetic energy = 32kTk is called Boltzmann constant, whose value is = 1
38064852 × 10-23 T= 27 0C = 300 KSo Translational kinetic energy = 32kT = 32 × 1
3806× 10-23  × 300                               = 1242
54 × 10-23This translational kinetic energy = Wavelength λCircumference 2πr = nλwhere n is the number of orbitCircumference 2πr = 5 × 1242
54 × 10-23 = 6212
7 × 10-23 m = 6
212 × 10-18 cm

find the circumference of the fifth bohr orbit of an electron whose de-brogile wavelength corresponds to translation kinetic energy of h at 27 degree celsius