find the co-ordinates of the point on the y axis which are at a distance of 5 units from the point (5,4)

take pt A (5,4) and B( 0,y)
therefore, AB = 5 units [given]
square both side
AB2 = 25
(0 - 5) 2+ (y - 4)2= 25
25 + (y - 4)2 = 25
(y - 4)2 = 0
y - 4 = 0
y = 4
i hope so!!


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