Find the coordinates of the foci vertices length of major and minor axis latus rectum of the following curve
36x2+4y2=144
Thegiven equation is 36x2+ 4y2= 144.
It can bewritten as
Here,the denominator of 
isgreater than the denominator of
.
Therefore,the major axis is along the y-axis,while the minor axis is along the x-axis.
Oncomparing equation (1) with
,we obtain b =2 and a =6.
Therefore,
Thecoordinates of the foci are
.
Thecoordinates of the vertices are (0, ±6).
Lengthof major axis = 2a =12
Lengthof minor axis = 2b= 4
Lengthof latus rectum 