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find the coordinates of the point where the diagonals of the parallelogram formed by joining the points (-2,-1),(1,0),(4,3)and

(1,2)

since the question is incomplete . i think you are looking for intersection points of diagonals of the given parallelogram.

diagonals of the parallelogram bisect each other.

let A(1,2),B(4,3),C(1,0) and D(-2,-1) are the vertices of the parallelogram.

diagonals AC and BD will intersect at their mid-point.

mid-point of AC=

mid-point of BD=

here from the data also we can see that AC and BD intersect at (1,1)

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 The diagonals of a parallelogram bisect each other. Here the point of intersection would be the point of bisection as well. That means if we calculate the mid points of the diagonals. It should be equal and same.

Let the given coordinates be the coordinates of a parallelogram ABCD. We will calculate the Mid points of DIagonal AC and BD. They should be same.

Mid points of a line segmant = (X1+X2) / 2 , (Y1+Y2) / 2

Mid points of diagonal AC = (-2+4) / 2 , (-1+3) / 2

The mid points are (1,1)

Mid points of Diagonal BD = (1+1) / 2 , (0+2) / 2

So the mid points of DIagonal BD = (1,1)

Both the mid points are same. Though the question is not complete and Clear but I hope that this is the answer you are looking for.

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