# find the current in each of the following

$a.45\xf7(-9)=-\frac{45}{9}=-5\phantom{\rule{0ex}{0ex}}b.1728\xf7(-12)=-\frac{1728}{12}=-144$

Regards

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$a.45\xf7(-9)=-\frac{45}{9}=-5\phantom{\rule{0ex}{0ex}}b.1728\xf7(-12)=-\frac{1728}{12}=-144$

Regards

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