Find the De Broglie wavelength of a neutron at 127?C Share with your friends Share 0 Vipra Mishra answered this Solution T = 127 + 273 =400 KEnergy of neutron at temperature TE =32kT=32×1.38×10-23×400 =828×10-23 Jλ =h2mEλ =6.63×10-342×1.66×10-27×828×10-23 =6.63×10-342748.96×10-50=6.63×10-3452.43×10-25λ =0.126×10-9 = 1.26 ×10-10 m 0 View Full Answer