Find the difference between heats of reaction at constant pressure and constant volume for the following reaction at 25 C in kJ.

2C6H6 + 15O2 ---------> 12CO2 + 6H2O.

The difference between heats of reaction at constant pressure and constant volume for the following reaction at 25 C in kJ.
2C6H6(l) + 15 O2(g)  12 CO2(g) + 6 H2O(l)n = 12 - 15 = -3H = E + RT nH - E   = RT n                       = (-3) × 8.314 × 10-3 × 298                       =- 7.443 kJ/mole

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