Find the difference of the areas of a sector of angle 120° and its correspondingmajor sector of a circle of radius 21 cm. Share with your friends Share 3 Varun.Rawat answered this Let θ be the central angle.Now, θ = 120°radius of the circle, r = 21 cmarea of the minor sector = θ360°πr2 = 120°360°×π212 = 441π3 cm2area of circle = πr2 = π212 = 441π cm2Now, area of major sector = area of circle - area of minor sector ⇒area of major sector = 441π - 441π3 =882π3 cm2Now, area of major sector - area of minor sector = 882π3 - 441π3 =441π3 cm2 = 4413 × 227 = 462 cm2 16 View Full Answer Mohammed Sanghar answered this minor sectorangle = 120 degreer=21cmarea = q/360 x PI x Rsquare=120/360 x 22/7 x 21 x 21=1/3 x 22/7 x 21 x 21=1 x 22 x 21=22 x 21=462Major sectorangle=360 - 120=240R = 21 cmArea = 240/360 x 22/7 x 21 x 21=2/3 x 22/7 x 21 x 21=2 x 22 x 21=480AREA OF MINOR SECTOR = 240 AND AREA OF MAJOR SECTOR = 480HOPE IT HELPS YOU THUMBS UP PLS 9 Mohammed Sanghar answered this SOORY I MEANT AREA OF MINOR SECTOR = 462 AND AREA OF MAJOR SECTOR =924 5