Find the difference of the areas of a sector of angle 120° and its corresponding
major sector of a circle of radius 21 cm.

Let θ be the central angle.Now, θ = 120°radius of the circle, r = 21 cmarea of the minor sector = θ360°πr2 = 120°360°×π212 = 441π3 cm2area of circle = πr2 = π212  = 441π cm2Now, area of major sector = area of circle - area of minor sector area of major sector =  441π - 441π3 =882π3 cm2Now, area of major sector - area of minor sector = 882π3 - 441π3 =441π3 cm2 = 4413 × 227 = 462 cm2

  • 16
minor sector
angle = 120 degree
r=21cm
area = q/360 x PI x Rsquare
=120/360 x 22/7 x 21 x 21
=1/3 x 22/7 x 21 x 21
=1 x 22 x 21
=22 x 21
=462

Major sector
angle=360 - 120
=240
R = 21 cm
Area = 240/360 x 22/7 x 21 x 21
=2/3 x 22/7 x 21 x 21
=2 x 22 x 21
=480
AREA OF MINOR SECTOR = 240 AND AREA OF MAJOR SECTOR = 480
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  • 9
SOORY I MEANT AREA OF MINOR SECTOR = 462 AND AREA OF MAJOR SECTOR =924
  • 5
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