find the dimension of rectangle whose perimeter is 112 cm and its breadth is 4 cm less than its half of its length

Dear student, 
perimeter of a rectangle = 2( length +breadth)let length be x cm therefore breadth will be x2-4 cm since perimeter is 112 cm112= 2(x+x2-4)56=x+x2-460=x+x23x2=60x=60×23x=40cmtherefore length=40cm and breadth=x2-4=402-4=16cm

Regards

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