find the dimensional formula of resistance R

 ML2T-3A-2

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[ML2T-3A-2]

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We have V=IR which implies R=V divided by I (R=V/I)

Also V=W/Q

Therefore R=W/(QI)

W=ML2T-2

Q=AT

I=A

Hence by substitution we get R=ML2T-3 A-2

Happy???????

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[ML2T-3A-2]
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​RESISTANCE DIMENSIONS = ML2T-3A-2
 
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R=V/I
        (REMEMBER V=W/Q)   
R=(W/Q)/I  (REMEMBER Q=IT) 
R=(W/IT)/I
R=(W/I*TIME)/I     {W=ML^2T^-2}
THEREFORE R=(ML^2T^-3A^-2)
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ML2T-3A-2
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[ML2T-3A-2]
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V=IR
V=ML2T-3A-1
I= A
R=V/I
R=ML2T-3A-1/A=ML2T-3A-2
 
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Dimensional formula of resistance (R):-
potential difference / current  
                    [unit---ohm]
=ML2T-3A-2
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Please find this answer

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This is the dimensional formula of resistance

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[ML^2T^-3A^-2]
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V/I = ML2T-3 A-1 /A = ML2T-3 A-2 
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ML?T-?A-?
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We know that,
V=IR
Therefore,
R=V/I
= dimensions of potential difference(V)/ dimensions of current (I)
= [M1L2T-3A-1] / [M0L0T0A1]
= [M1L2T-3A-2]
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[ML^2 I^-2 T^-3]
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Resistance (R) - Potential Difference/Current..
Therefore ML^2T^-3A^-1
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DeltaP/p*100= 3delta a/a*100 +2delta b/b *100 + 1/2 delta c/c*100 + delta d/d*100 DeltaP/p*100= 3(1) +2(3) +1/2(4) +1(3) =3+6+2+3 =14% Therefore deltaP/p*100= 14%
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R=V/I

Also V=W/Q

Therefore R=W/(QI)

W=ML2T-2

Q=AT

I=A

Hence by substitution we get R=ML2T-3 A-2
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ML2T-2 is the dimensional formula of R
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M1L2T-3A-2

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We know that , V=IR Dimensional formula of "V" is ML2T-3A-1 Dimensional formula of "I" is A Dimensional formula of Resistance(R) = V/I = ML2T-3A-1/A = ML2T-3A-2
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The formula relates the resistance of a conductor with its specific resistance (the Greek letter ?rho? (?), which looks similar to a lower-case letter ?p?), its length (?l?), and its cross-sectional area (?A?). Hari om, you are asking a question as to: ?What is the dimensional formula of specific resistance??. Hari om.
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We have V=IR which implies R=V divided by I (R=V/I)

Also V=W/Q

Therefore R=W/(QI)

W=ML2T-2

Q=AT

I=A

Hence by substitution we get R=ML2T-3 A-2
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Rho. it looks like small p in english letter
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M L? T-? I-?
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Resistance is a constant so it is dimensionless
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ML^2T^-3I^-2
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I think [L]1
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ML^2T^-3A^-2

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ML?T-?I-?

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The unit of resistance is ohm and the dimension is [M1 L2 T-3 A-1]
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ML^(2)T^(-3)A(^-2)
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?ML2T-3A-2
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Dimensional formula of Resistance R is [ ML^2T^-3A^-2]
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Dimensional formula for resistance is M?L?T^-?A^-?
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R=V/I
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Dimensional formula of resistance R
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cubed electric current squared.
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Resistance is constant.
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resistance is equal to voltage divided by current
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7,8,9,6,7,8,5,
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R=rho*l*a
So.. rho-constant, l- lenghth of conducting material
A-cross sectional area

L/L*L =L ka power -1
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resistance?is dimensionally represented as M L2?T-3?I-2.
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( ML^2T ^-3A^-2)
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[ML^2 T^-3A^-2]
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