# find the dimensional formula of resistance R

ML2T-3A-2

• 16

[ML2T-3A-2]

• 20

We have V=IR which implies R=V divided by I (R=V/I)

Also V=W/Q

Therefore R=W/(QI)

W=ML2T-2

Q=AT

I=A

Hence by substitution we get R=ML2T-3 A-2

Happy???????

• 80
[ML2T-3A-2]
• 1
​RESISTANCE DIMENSIONS = ML2T-3A-2

• 5
R=V/I
(REMEMBER V=W/Q)
R=(W/Q)/I  (REMEMBER Q=IT)
R=(W/IT)/I
R=(W/I*TIME)/I     {W=ML^2T^-2}
THEREFORE R=(ML^2T^-3A^-2)
• 5
ML2T-3A-2
• 4
[ML2T-3A-2]
• 14
V=IR
V=ML2T-3A-1
I= A
R=V/I
R=ML2T-3A-1/A=ML2T-3A-2

• 25
Dimensional formula of resistance (R):-
potential difference / current
[unit---ohm]
=ML2T-3A-2
• 2 • -6
This is the dimensional formula of resistance • 45
[ML^2T^-3A^-2]
• -1
V/I = ML2T-3 A-1 /A = ML2T-3 A-2
• 9
ML?T-?A-?
• 2
We know that,
V=IR
Therefore,
R=V/I
= dimensions of potential difference(V)/ dimensions of current (I)
= [M1L2T-3A-1] / [M0L0T0A1]
= [M1L2T-3A-2]
• 1
Force acting on a body is F=A cos BX + c sin Dt.find the dimension of D÷B where X and T are displacement and time
• 3
Which is the most accurate atomic clock ?
• 2
its a secret ^_^
• -4
wait a minute
• -3
[ML^2 I^-2 T^-3]
• -1
Resistance (R) - Potential Difference/Current..
Therefore ML^2T^-3A^-1
• -2
DeltaP/p*100= 3delta a/a*100 +2delta b/b *100 + 1/2 delta c/c*100 + delta d/d*100 DeltaP/p*100= 3(1) +2(3) +1/2(4) +1(3) =3+6+2+3 =14% Therefore deltaP/p*100= 14%
• 1
If percentage error in measurement of radius is 2%. Find percentage error in measurement of surface area of sphere.
• -2
Look image • 0 • 1 • -2
R=V/I

Also V=W/Q

Therefore R=W/(QI)

W=ML2T-2

Q=AT

I=A

Hence by substitution we get R=ML2T-3 A-2
• 1
ML2T-2 is the dimensional formula of R
• -1 • 0
explain the digestive system of human
• -1 • 0 • 0 • 0
M1L2T-3A-2 • 1
Wronggggv
• 0 • 1
abcd
• -2
We know that , V=IR Dimensional formula of "V" is ML2T-3A-1 Dimensional formula of "I" is A Dimensional formula of Resistance(R) = V/I = ML2T-3A-1/A = ML2T-3A-2
• -1
The formula relates the resistance of a conductor with its specific resistance (the Greek letter ?rho? (?), which looks similar to a lower-case letter ?p?), its length (?l?), and its cross-sectional area (?A?). Hari om, you are asking a question as to: ?What is the dimensional formula of specific resistance??. Hari om.
• 1
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• 1
We have V=IR which implies R=V divided by I (R=V/I)

Also V=W/Q

Therefore R=W/(QI)

W=ML2T-2

Q=AT

I=A

Hence by substitution we get R=ML2T-3 A-2
• 1
Rho. it looks like small p in english letter
• 0 • 0
M L? T-? I-?
• 0
Resistance is a constant so it is dimensionless
• 0
ML^2T^-3I^-2
• 0 • 0
I think [L]1
• 0
ML^2T^-3A^-2 • 1 • 0
ML?T-?I-? • 0
The unit of resistance is ohm and the dimension is [M1 L2 T-3 A-1]
• 0
ML^(2)T^(-3)A(^-2)
• 0
?ML2T-3A-2
• 0
What should be the duration of the year of the distance between the sun of the earth get doubled the present distance
• 0
Dimensional formula of Resistance R is [ ML^2T^-3A^-2]
• 0
Dimensional formula for resistance is M?L?T^-?A^-?
• 0
R=V/I
• 0 • 0
Jal Chakra Kise Kahate Hain
• 0
Dimensional formula of resistance R
= Length squared mass per time
cubed electric current squared.
• 1
Resistance is constant.
so R=dimensionless.
• 0
resistance is equal to voltage divided by current
• 0
7,8,9,6,7,8,5,
• 0
R=rho*l*a
So.. rho-constant, l- lenghth of conducting material
A-cross sectional area

L/L*L =L ka power -1
• 0
mlg Roti zero
• 0
resistance?is dimensionally represented as M L2?T-3?I-2.
• 0
Aman
• 0
so Kyon Ne Anna use Hindi mein Kaise likhen
• 0
( ML^2T ^-3A^-2)
• 0
can you help me • 0 