find the distance between 2 points in a 3 dimensional plane and hence find the distance between the points p(-2,3,5) and Q(1,2,3)

Distance between two points P(x₁, y₁, z₁) and Q(x₂, y₂, z₂) is,

P Q = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2} + {(z_{2} - z_{1})}^{2}}

so the distance between, (-2, 3, 5) and (1, 2, 3) is given by :

d i s \tan c e = \sqrt{{(1 - (- 2))}^{2} + {(2 - 3)}^{2} + {(3 - 5)}^{2}} = \sqrt{(3)^{2} + (- 1)^{2} + (- 2)^{2}} = \sqrt{9 + 1 + 4} = \sqrt{14} u n i t s