find the distance between following parallel lines (i) 2x+3y-4=0 and 2x+3y+17=0 Share with your friends Share 2 Varun.Rawat answered this The given equations are :2x + 3y - 4 = 02x + 3y + 17 = 0Comparing it with a1x+ b1y + c1 = 0 and a2x + b2y + c2 = 0Now, a1 = 2, b1 = 3 and c1 = -4a2 = 2; b2 = 3; c2 = 17Now, distance between parallel lines = c1-c2a12+b12 = -4-1722 + 32 = 214 + 9 = 2113 units = 211313 units 8 View Full Answer
