Find the distance between the straight lines 5x-3y-4=0 and 10x-6y-9=0. Share with your friends Share 3 Rahul Raj answered this The given lines are :5x - 3y - 4 = 0 ...110x - 6y - 9 = 0⇒5x - 3y - 92 = 0 ....2Now, clearly the slopes of given lines are equal so they are parallel.Now, comparing the above equations with ax + by + c1 = 0 and ax+by+c2 = 0, we geta = 5; b = -3; c1 = -4; c2 = -92Now, distance = c2-c1a2+b2 = -92+452+-32 = 1234 units 10 View Full Answer
