Find the distance of the point (3,4,5) from the plane x+y+z= 2 measured parallel to line 2x = y = z.............answer it fast

The line 2x=y=z

can be written as x=y/2=z/2

The line passing through (3,4,5) and parallel to the given line can be written as x-3/1=y-4/2=z-5/2=k

Therefore an point can be written as x=k+3,y=2k+4,z=2k+5

Since this lies on the plane substituting these coordinates in the equation of the plane.

k+3+2k+4+2k+5=2

5k=-10

k=-2;

Therefore the coordinate is (1,0,1)

The distance =sqrt( (4+16+16)

=sqrt(36)

= 6 units