Find the distance of the point (-3 -4) from the x -axis (in units).

Dear Student,

At x-axis y co-ordinate = 0, So point at x-axis is -3,0P=-3,0, Q=-3, -4PQ= x2-x12+y2-y12= -3--32+-4-02= 02+-42= 16= 4 units

Regards

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