find the equation of a line perpendicular to the line x- 2y +3 = 0 and passing through the points (1,-2) Share with your friends Share 0 Anuradha Sharma answered this Slop of line x-2y+3=0 is = 12So slop of line perpendicular to it = -112=-2So equation of line pasing from 1,-2 and having slop -2 isy+2=-2x-12x+y=0 -1 View Full Answer
