find the equation of circle passing through origin of radius 5 and x- intercept substend anangle of 60 degree at the centre

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Please find below the solution to the asked query:

It is given that ORsubtends 60° at centre.a,b are coordinates of centreNow OPQ=30°r=OP=5OQ=asin30°=a512=a5a=52a=±52cos30°=b532=b5b=532b=±532Hence equations will bex-522+x-5322=25 orx+522+x-5322=25 orx-522+x+5322=25 orx+522+x+5322=25

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