find the equation of straight lines which are perpendicular to the line 12x + 5y = 17  and at a distance of 2 units from point v(-4,1 )

the equation of the given line is 12x+5y=17
slope of the line = -12/5
slope of the line which is perpendicular to the given line is 5/12.
let the equation of the required line is 
y=512x+c12y=5x+12c5x-12y+12c=0 .........(2)now if the perpendicular distance of the line (2) from point (-4,1) is 2 units5*(-4)-12*1+12c52+122=2-20-12+12c169=2-32+12c13=2
-32+12c13=±2-32+12c=±2612c=32±2612c=32+26 or 12c=32-2612c=58 or 12c=6
thus the equations of the required lines are
12y=5x+58 or 12y=5x+6

hope this helps you

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