Find the equation of the bisector of  ∠A of ∆ABC whose vertices are A(4,3),B(0,0) and C(2,3).

A(4, 3), B (0, 0) and C(2, 3) are the vertices of ΔABC.

AD is the bisector of ∠A.

∴ Coordinates of D

Equation of the straight line passing through (x1, y1) and (x2, y2) is (yy1) = (xx1).

∴ Equation of AD is

Thus, the equation of AD is x – 3y + 5 = 0.

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As Line bisects angle A thats why its must be passing through the centeroid &will also be perpendicular to BC, now find coordinates of centeroid & then slope of solve it further like that foot of perpendicular.

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