Find the equation of the bisector of ∠A of ∆ABC whose vertices are A(4,3),B(0,0) and C(2,3).

A(4, 3), B (0, 0) and C(2, 3) are the vertices of ΔABC.

AD is the bisector of ∠A.

∴ Coordinates of D

**Equation of the straight line passing through (****x**_{1}**, ****y**_{1}**) and (****x**_{2}**, ****y**_{2}**) is (****y**** – ****y**_{1}**) = (****x**** – ****x**_{1}**).**

∴ Equation of AD is

Thus, the equation of AD is *x* – 3*y* + 5 = 0.

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