Find the equation of the bisector of ∠A of ∆ABC whose vertices are A(4,3),B(0,0) and C(2,3).
A(4, 3), B (0, 0) and C(2, 3) are the vertices of ΔABC.
AD is the bisector of ∠A.
∴ Coordinates of D
Equation of the straight line passing through (x1, y1) and (x2, y2) is (y – y1) = (x – x1).
∴ Equation of AD is
Thus, the equation of AD is x – 3y + 5 = 0.