# Find the equation of the circles which touch the axis of x at a distance of 4 from the origin and cut off an intercept of 6 from the axis of y A circle having its centre in the first quadrant touches the y axis at a point (0,2) and passes through the point (1,0).Find the equation of the circle  calculate the co ordinatesof the foot of the perpendicular from the point (-4,2)to the line 3x+2y=5 . find the equation of the smallest circle passing through(-4,2) and having its centre on the line 3x+2y=5

(1) The given problem can be represented as given above.

Intercept on y– axis = 6

As circle touches the x– axis at a distance of 4 from the origin, so there are two such circles possible.

E is the mid-point of CD. Join OE, OC and OA. So, coordinate of centre or point O = (± 4, 5).

Hence, equation of the circle, Due to paucity of time it would not be possible for us to provide the answers to all your queries. We are providing solutions to some your good queries. Try solving rest of the questions yourself and if you face any difficulty then do get back to us.

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