find the equation of the ellipse whose eccentricity is 3/4 ,focuson the y axis and passing through the point (6,4)
General equation of ellipse with focus on y -axis is
And e =
And the ellipse is passing through (6,4)
And b2 = a2 (1-e2 )
So putting the point ( 6,4) in general equation, we get 16/a2 + 36/b2 = 1 (1)
So
And
So the equation of the ellipse will be y2 /(688/7) + x2 / (43) = 1
And e =
And the ellipse is passing through (6,4)
And b2 = a2 (1-e2 )
So putting the point ( 6,4) in general equation, we get 16/a2 + 36/b2 = 1 (1)
So
And
So the equation of the ellipse will be y2 /(688/7) + x2 / (43) = 1