Find the equation of the line passing through the point ( -4, -5) and perpendicular to the line joining the points (1, 2) and (5, 6)?

Slop of line passing through 1,2 and 5,6=6-25-1=1So slop of line perpendicular to it = 1-1=-1Now equation of line passing through -4,-5 and having slop -1 is, y+5=-1x+4x+y+9=0

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