Find the equation of the line perpendicular to 2x+3y+10=0 and whose Y-interceptexceeds X-intercept by 2. I want answer with full solution. Share with your friends Share 0 Anuradha Sharma answered this Equation of a line perpendicular to 2x+3y+10 =0 is 3x-2y+k = 0 Now x axis intercept will be at y = 0 so, x = -k3and y -axis intercept will be at x = 0 so, 2y = ky = k2It is given that , k2= -k3+25k6= 2 k = 125So equation of the line is, 3x-2y+125 = 0 15x-10y+12=0 0 View Full Answer
