Find the equation of the locus of a point whose distance from y axis is equal to distane from (2,1,-1) ? ANS y2-2y-4x+2z+6=0 Share with your friends Share 6 Physicsmannn answered this ANS is y2-2y-4x+2z+6=0 -9 View Full Answer Huma Fatima answered this Any point on Yaxis=0(0,y,,0)=P Q=(2,1,-1)&A=(x,y,z) A.T.Q root of (x-0)2+(y -0)2+(z -0)2=root of (x-2)2+(y -1)2+(z+1)2 x 2 + 0 +z 2 =x 2 +4 -4x+ y 2 +1 -2 y+z 2 +1+2 z 4 x - y2-1+2 y -1 -2 z=4=0 y2-2 y -4 x+ 2 z+6=0 14 Gufty answered this Dont know solve by your own 0
