Find the equation of the locus of a point whose distance from y axis is equal to distane from (2,1,-1) ?  ANS  y​2-2y-4x+2z+6=0

ANS is y2-2y-4x+2z+6=0
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Any point on Yaxis=0(0,y,,0)=P
Q=(2,1,-1)&A=(x,y,z)
A.T.Q
root of (x-0)2+(y -0)2+(z -0)2=root of (x-2)2+(y -1)2+(z+1)2
+ 0 +z =x +4 -4x+ y 2 +1 -2 y+z +1+2 z
4 x - y2-1+2 y -1 -2 z=4=0
y2-2 y  -4 x+ 2 z+6=0
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